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ncert maths class 10 chapter 15 solutions

ncert maths class 10 chapter 15 solutions

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Total numbers of students = 40. Numbers of students = 6. Required probability = 6/40 = 3/20

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Ans : (i) Highest number = 9 (ii) Lowest number = 1 (iii) Range = (9 - 1) = 8 (iv) Sum of all the observations = 4 + 6 + 7 + 5 + 3 + 5 + 4 + 5 + 2 + 6 + 2 ...

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It can be observed clearly that the most common blood group and the rarest blood group among these students is O and AB respectively as 12 (maximum number ...

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For this A.P., a = 9 d = a2 – a1 = 17 – 9 = 8

As the number of observations is 10. 10 is an even number. So, median score will be

Mean, ¯¯¯x=a+(∑fiui∑fi)h=32.5+(−2335)×5=32.5−237=32.5−3.28=29.22 Mean, x ¯ = a + ( ∑ f i u i ∑ f i ) h = 32.5 + ( − 23 ...

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For this A.P., a = 9 d = a2 – a1 = 17 – 9 = 8

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